A helium atom (m = 6.646 × 10−27) collides elastically with an oxygen atom (m = 2.656 × 10−26) at rest. After the collision, the helium atom is found to be moving with a velocity of 6.636×106 m/s in a direction at an angle of 84.7◦ relative to its original direction. The oxygen atom is observed to move at an angle of -40.4◦.
(a) Find the velocity of the oxygen atom after the collision.
(b) Find the speed of the helium atom before the collision.
Answers: 3
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A helium atom (m = 6.646 × 10−27) collides elastically with an oxygen atom (m = 2.656 × 10−26) at re...
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