An electron is released from rest in a vacuum between two flat, parallel metal plates that are apart and are maintained at a constant electric potential difference of Volts. If the electron is released at the negative plate, what is its speed just before it strikes the positive plate?

v = √(2qV/m)

Explanation:

½mv² = qV

mv² = 2qV

v² = 2qV/m

v = √(2qV/m)

where v = drift velocity

q = charge

V = p.d

m = mass of the electron

scorpions are,

c.arachnids

  scorpions are animals in the order scorpiones, under the class arachnida, which makes them a distant cousin of spiders

happy to

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your answer is c! hope this : )