A squirrel runs along an overhead telephone wire that stretches from the top of one pole to the next. It is initially at position x i = 3.47 m , as measured from the center of the wire segment. It then undergoes a displacement of Δx = − 6.29 m . What is the squirrel's final position xf ?

The the squirrel's final position is  − 2.82 m

Explanation:

ΔX = Xf - Xi

Where;

ΔX is the  displacement  in the squirrel's position = − 6.29 m

Xf  is the the squirrel's final position = ?

Xi is the the squirrel's initial position = 3.47 m

From the equation above

Xf = ΔX  + Xi

Xf = (− 6.29 + 3.47) m

Xf = − 2.82 m

Therefore, for a squirrel with an initial position of 3.47 m and displacement in position as − 6.29 m, the final position will be − 2.82 m

answer: the rock sample is a sedimentary rock.

explanation:

it is given that:

mass of rock sample, m = 2.7 g

volume of rock sample,

so, density of rock sample will be

since, the density of rock sample is . hence, the rock sample is a sedimentary rock, whose densities varies between .