A battery with an emf of 12.0 V shows a terminal voltage of 11.4Vwhen operating in a circuit with two lightbulbs, each rated at 4.0 W(at 12.0 V),which are connected in parallel. What is the battery's internal resistance?

Express your answer to two significant figures and include the appropriate units.

0.95 A

Explanation:

P = Power of bulb = 4 W

V = Voltage = 12 V

Power is given by

The connections are in Parallel

Equivalent resistance of these two bulb

Current from the source

The voltage drop is

Voltage drop is given by

The internal resistance is 0.95 A

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