Calculate the ratio of the drag force on a passenger jet flying with a speed of 950 km/h at an altitude of 10 km to the drag force on a prop-driven transport flying at one-fifth the speed and half the altitude of the jet. At 10 km the density of air is 0.38 kg/m3 and at 5.0 km it is 0.67 kg/m3. Assume that the airplanes have the same effective cross-sectional area and the same drag coefficient C.

14.18

Explanation:

given,

Speed of passenger jet,v₁ = 950 Km/h

Altitude of flight, h₁ = 10 km

Prop-driven speed,v₂ = 950/5 = 190 Km/h

altitude,h₂ = 5 Km

density of air at 10 Km = 0.38 Kg/m³

density of air at 5 Km = 0.67 Kg/m³

Drag force formula

now, ratio of drag Force

Hence, the ration of the drag force is equal to 14.18.

305.7

explanation:

density =m/v

density =917/3.00

density = 305.

approximately = 305.7

in four significant figures