A displacement vector of magnitude 10m has its y-component of 4m. What is the angle of vector made with the x-axis.

∅ = inverse sin of (0.4) = 23.58°

Explanation:

Let ∅ be the angle made by the vector with the x axis.

The given displacement vector's y component  is 4 m and the magnitude of the given displacement vector is 10 m

We know that sin ∅ = opposite side / hypotenuse

Here ,  the given displacement vector 's y component  is the opposite side and the magnitude of the given displacement vector is the hypotenuse.

Hence sin ∅ = 4/10  = > 0.4

          ∅ = inverse sin of (0.4) = 23.58° (Computed using the calculator)

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