IP Consider a parallel-plate capacitor constructed from two circular metal plates of radius R. The plates are separated by a distance of 1.4 mm .
(a) What radius must the plates have if the capacitance of this capacitor is to be 1.8

Required radius of the plates = 9.52 m

Explanation:

C = (Aε₀)/d

C = 1.8 × 10⁻⁶ F

A = ?

ε₀ = 8.8542 × 10⁻¹² F/m

d = 1.4 mm = 1.4 × 10⁻³ m

A = Cd/ε₀ = (1.8 × 10⁻⁶)(1.4 × 10⁻³)/(8.8542 × 10⁻¹²) = 281.61 m²

Area of the plate = πr² = 281.61

r² = 281.61/π = 90.59

r = √(90.59) = 9.52 m

t2 equal the displacement of the particle over the same time period if t2> t/2? hint: consider a sine wave starting at t1=0, then consider a closing wave starting at t1=0, for your explanatio

electrical to thermal