A ski lift carries a 75.0-kg skier at 3.00 m/s for 1.50 min along a cable that is inclined at an angle of 40.0° above the horizontal. a. How much work is done by the ski lift? b. How much power is expended by the ski lift?

Answer

given,

mass of the ski = 75 Kg

speed of the skier, v = 3 m/s

time = 1.50 min = 90 s

angle of inclination, θ = 40°

distance = s x t

              = 3 x 90 = 270 m

a) W = F. d cos θ

   W = mg. d cos θ

   W = 75 x 9.8 x 270 x cos 40°

    W = 152021.52 J

work is done by the ski lift is equal to  152021.52 J

b) Power extended by the ski

      P = 1689.13 Watt.

power is expended by the ski lift is equal to 1689.13 W.

a, c, d, e are all applying about success strategies.

electrical potential energy =0.072 j

explanation:

electrical potential energy is given by

u= q δv

q= charge=6 c

δv= potential difference and is given by

δv= e d

e= electric field

d= distance=5 mm=0.005 m

δv=2.4 (0.005)=0.012 v

now electric potential energy= u= q δv

u=6 (0.012)

u=0.072 j