Air becomes a conductor when the electric field strength exceeds 3.01 × 106 N/C. Determine the maximum amount of charge that can be carried by a metal sphere 5.0 m in radius. The value of the Coulomb constant is 8.99 × 109 N · m2 /C 2 . Answer in units of C.

8.37×10⁻³ C.

Explanation:

The formula of electric field is given as

E = kq/r² Equation 1

Where E = electric field, q = amount of charge, k = coulomb constant, r = radius of the sphere

make q the subject of the equation

q = Er²/k Equation 2

Given: E = 3.01×10⁶ N/C, r = 5.0 m, k = 8.99×10⁹ Nm²/C².

Substitute into equation 2

q = (3.01×10⁶)(5²)/(8.99×10⁹)

q = (75.25/8.99)×10⁻³

q = 8.37×10⁻³ C.

Hence the maximum amount of charge = 8.37×10⁻³ C.

show the wavelengths of a wave. show the crests of a wave.

weight of the box is given as

here this is placed on the inclined of angle 42 degree

now this weight will have two components one is along the incline other is perpendicular to it

so here we need to apply a force parallel to incline opposite to its component of weight

so here the component of weight is given as

here we have

so it requires 75 n force to move it upwards