A +0.2 μC charge is at some point P in an electric field. Part A What happens if that charge is replaced by a +0.4 μC charge?

Explanation:

given,

Charge,q = +0.2 μC

using equation of electric field

r is the distance of the position where electric field is to be calculated.

k is coulomb constant

when q =  +0.2 μC

when charge is changed to q' = +0.4 μC

         distance is same r' = r

From, the above equation we can conclude that when the charge +0.2 μC is replaced by +0.4 μC the electric field of the system is doubled.

pe = weightxheight = 2000x1000=2,000,000joules

weight of the box is given as

here this is placed on the inclined of angle 42 degree

now this weight will have two components one is along the incline other is perpendicular to it

so here we need to apply a force parallel to incline opposite to its component of weight

so here the component of weight is given as

here we have

so it requires 75 n force to move it upwards