Here we will calculate the work per unit charge on an electron moving between two potentials. A 9.0 V battery is connected across two large parallel plates that are separated by 4.5 mm of air, creating a potential difference of 9.0 V between the plates. (a) What is the electric field in the region between the plates? (b) An electron is released from rest at the negative plate. If the only force on the electron is the electric force exerted by the electric field of the plates, what is the speed of the electron as it reaches the positive plate? The mass of an electron is me=9.11×10−31kg.

2000 V/m

1778021.69323 m/s

Explanation:

V = Voltage = 9 V =

q = Charge of proton =

m = Mass of electron =

v = Velocity of electron

Electric field is given by

The electric field is 2000 V/m

Here, the energy of the system is conserved

The velocity of the electron is 1778021.69323 m/s

diagram is missing, but i will try to explain your doubt.

answer:

amplitude is the maximum displacement or distance moved on a point of a vibrating body or wave measured from its equilibrium position.it is equal to half the length of vibration path.

the chart show the masses and velocities of two colliding objects that stick together after a collision.

according to the law of conservation of momentum, the momentum of the object after the collision is  

answer

1,500

kg • m/s.