An object is thrown directly upwards from the ground at a velocity of 9ms. Recalling that the acceleration due to gravity is −gms2, find the time at which the object reaches its maximum height. What is this maximum height? Your answers should be in terms of g.

Explanation:

Given

Object is thrown with a velocity of

Acceleration due to gravity is -g (i.e. acting downward)

Vertical distance traveled by object is given by

where v=final velocity

u=initial velocity

a=acceleration

s=displacement

at maximum height final velocity is zero

time taken to reach maximum height

using

v=u+at

0=9-gt

the answer would be 32*f

force tends to be low and long diustance masses are high