If the position is 60m above the ground and the kinetic energy is 20,000 units, can you tell me the potential energy is plz be quick

Explanation:

During upward or downward motion of ground the kinetic energy and potential energy are interchangeable.

At a certain height h potential energy= P.E

P.E= mgh

Since h=60 m

So P.E= m× 9.8m/s²× 60m

P.E= 588m

Where m is the mass of the object and is unknown.

At height of 60 meters the Kinetic energy K.E of the body is 20,000.

Since K.E = (1/2)mv²

20,000= (1/2)mv²

v= √(40000/m)

By using the third equation of motion

v²= u²+ 2gh

Here u is the initial velocity and v is the final velocity

The initial velocity during motion under the effect of gravity is always zero

So

v =√(2gh)

v=√(2×9.8m/s²×60m)=34.3 m/s

By using this value of v in the above equation

v²=40,000/m

Or

m= 40, 000/v²

m=34kg

Hence potential energy

P.E= 588×34

=19991 which is almost equal to K.E.

what is the question?

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