A uniform solid ball rolls smoothly along a floor, then up a ramp inclined at 33.0°. It momentarily stops when it has rolled 1.70 m along the ramp. What was its initial speed?

v = 3.6 m/s

Explanation:

given,

Inclination of the ramp, θ = 33⁰

Distance of the rope, d = 1.70 m

initial speed = ?

using conservation of energy

h = d sinθ  

h = 1.7 x sin 33° = 0.926 m

moment of inertia of the solid ball

we know, v = r ω

v = 3.6 m/s

Hence, initial speed of the solid ball = 3.6 m/s

i think it would be 80 km/h because 30 + 50 = 80 (sorry if this not the right answer i'm trying my best)

568.98

explanation:

its math