Acertain spring is found not to obey hooke’s law; it exerts a restoring force fx(x)=−αx−βx2 if it is stretched or compressed, where α=60.0n/m and β=18.0n/m2. the mass of the spring is negligible. (a) calculate the potential-energy function u(x) for this spring. let u = 0 when x = 0. (b) an object with mass 0.900 kg on a frictionless, horizontal surface is attached to this spring, pulled a distance 1.00 m to the right (the +x-direction) to stretch the spring, and released. what is the speed of the object when it is 0.50 m to the right of the x = 0 equilibrium position?

Answertraveling around a circular trackexplanation"traveling around a circular track" is the best answer as you could be traveling around a circular track at a constant speed. your velocity would therefore have the same magnitude but will always be constantly direction. since acceleration is the rate of change of velocity, the rate of change will only involve the direction of velocity and not the magnitude.wrong choices: "an object at rest" does not accelerate at all"increasing speed while traveling around a curve" means that the acceleration will not be constant due to only change in direction; it will be constant due to both magnitude and direction"an object in free fall" does not necessarily change direction