Apositive test charge q is released from rest at distance r away from a charge of +q and a distance 2r away from a charge of +2q.
how will the test charge move immediately after being released?

a. to the left
b. to the right
c. stay still
d. other

The test charge will move to the left side after being released.

Explanation:

Given that,

Test charge = q

First charge = Q

Second charge = 2Q

Distance of point charge from first charge = r

Distance of point charge from second charge = 2r

Let the charge Q placed at left side and charge 2Q placed at right side.

We need to calculate the force due to first charge

Using formula of force

Put the value into the formula

...(I)

We need to calculate the force due to second charge

Using formula of force

...(I)

Divided equation (I) by equation (II)

Hence,The test charge will move to the left side after being released.

part 1: which substance has a higher solubility?

a

smallest amount left undissolved atall temps in table shown most has dissolved high sol'by

the ima (higher than 1m) will be greater than the ima with the height of 1m.