(1) develop an equation that relates the rms voltage of a sine wave to its peak-to-peak voltage. a. if a sine wave has a peak-to-peak value of 1.5v, a frequency of 3khz, and a phase of 0 radians, what is the rms voltage

(A) Equation will be

(B) RMS value of voltage will be 0.530 volt

Explanation:

We have given peak to peak voltage of ac wave = 1.5 volt

Peak to peak voltage of ac wave is equal to 2 times of peak voltage

So

Frequency of ac wave is given f = 3 kHz

So angular frequency = 2×3.14×3000 = 18840 rad/sec

So expression of equation will be ( As phase difference is 0 )

Now we have to find the rms value of voltage

So rms voltage will be equal to

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