The legs of a weight lifter must ultimately support the weights he has lifted. a human tibia (shinbone) has a circular cross section of approximately 3.6 cm outer diameter and 2.30 cm inner diameter. (the hollow portion contains marrow.)if a 90.0 kg lifter stands on both legs, what is the heaviest weight he can lift without breaking his legs, assuming that the breaking stress of the bone is 150 mpa ?
Answers: 2
= Breaking stress of bone = 150 MPa
= Outer diameter = 3.6 cm
= Inner diameter = 2.3 cm
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The legs of a weight lifter must ultimately support the weights he has lifted. a human tibia (shinbo...
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