In a vacuum, two particles have charges of q1 and q2, where q1 = +3.11 μc. they are separated by a distance of 0.241 m, and particle 1 experiences an attractive force of 3.44 n.
what is the magnitude and sign of q2?

Charge of particle 2,

Explanation:

Given that,

Charge 1,

The distance between charges, r = 0.241 m

Force experienced by particle 1, F = 3.44 N

We need to find the magnitude of electric charge 2. It can be calculated using formula of electrostatic force. It is given by :

or

So, the magnitude of electric charge 2 is . Since, the force is attractive then the magnitude of charge 2 must be negative.