Ahigh-speed drill reaches 2300 rpm in 0.54 s. a) what is the drill's angular acceleration? b. through how many revolutions does it turn during this first 0.50 s?

The angular acceleration of the drill is 446.1 rad/s².

The number of revolutions of the drill in 0.5 second is 19.2 revolutions.

The given parameters;

The angular speed in radian per second is calculated as follows;

The angular acceleration of the drill is calculated as follows;

The number of revolutions of the drill in 0.5 second is calculated as follows;

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(A)Angular acceleration,

(B) Number of revolution is 8.87.

Explanation:

Given ,time taken to reach 2300 rpm speed from 0 is ,t = 0.54 s.

2300 rpm = 240.85 rad/s

(A) Applying equation of motion to find the drill's angular acceleration

(B) Let there are number of revolutions it turn during this first 0.50 s. It can be calculated using second equation of motion as :

Radian can be converted to revolution as :

Therefore, this is the required solution.

hi,

what occurs during a solar eclipse?

there are small tides across earth.

the moon is between earth and the sun.

p.s. im not sure if the first answer is correct because during a solar ecliphse there are spring tides and i dont know if they are the same.

in order to follow the instructions and complete the statements, i need to use data from table c of your student guide. can you think of a way to let me see your student guide for a while ? i can't answer the question without the data in table c.