High power lasers in factories are used to cut through cloth and metal. one such laser has a beam diameter of 0.863 mm and generates an electric field at the target having an amplitude 0.955 mv/m. the speed of light is 2.99792 × 10⁸ m/s the permeability of free space is 4π × 10⁻⁷ t· n/a. what is the amplitude of the magnetic field produced? answer in units of t.

B_m = 3.186 x 10⁻³ T

Explanation:

given,

diameter of the beam = 0.863 mm

Amplitude = 0.955 MV/m

speed of light = 2.99792 × 10⁸ m/s

he permeability of free space= 4π × 10⁻⁷ T· N/A

Amplitude of the magnetic field is given by

E_m is amplitude of the electric field.

     B_m = 0.31855 x 10⁻² T

     B_m = 3.186 x 10⁻³ T

The amplitude of magnetic field is equal to 3.186 x 10⁻³ T

I= 12.09×10^8 W/m^2

Explanation:

Em = amplitude of electric field = 0.955 MV/m = 0.955 x 10^6 V/m

B_m = amplitude of magnetic field = ?

c = speed of light = 2.99792 x 10^8 m/s

amplitude of magnetic field is given as

B_m = E_m /c

B_m = (0.955 x 10^6)/(2.99792 x 10^8 )

B_m = 0.00318 T

b)

intensity is given as

I= 1209873759.69

I= 12.09×10^8 W/m^2

the answer is a. at the equator

yup its correct its: c) b b