A200 kg ball is dropped from a height of 2m, bounces on a hard floor and rebounds to a height of 1.5m. what maximum force does the floor exert on the ball?

Correct question:a 200 g ball is dropped from a height of 2m, bounces on a hard floor and rebounds to a height of 1.5m. What maximum force does the floor exert on the ball?

The diagram of the question is in the attachment.

Explanation:

V=√2gh

g-10m/s²

let u be initial velocity ad v be final velocity,

u=√2*10*2

u=6.324m/s

v=√2*10*1.5

v=5.477m/s

from the diagram

t=5ms=0.005s

F=-33.87N    (the negative shows direction)

From the diagram Fmax=2F

   Fmax= 2*33.87

=67.74N

the chart show the masses and velocities of two colliding objects that stick together after a collision.

according to the law of conservation of momentum, the momentum of the object after the collision is  

answer

1,500

kg • m/s.