Apositively charged particle initially at rest on the ground accelerates upward to 140 m/s in 2.10 s. the particle has a charge-to-mass ratio of 0.100 c/kg and the electric field in this region is constant and uniform. what are the magnitude and direction of the electric field?

764.7 N/C, the direction is upward

Explanation:

E electric field of  the electron = F / charge

F force of the electron = Eq

acceleration of the body = change in velocity / time = 140 m / 2.10 s = 66.67 m/s² since the electron is from rest.

F upward = F of electron - force of gravity

F upward = Eq - mg

ma = Eq -mg

divide through with m

a = E (q/m) - g

(a + g) / (q/m) = E

(66.67 + 9.8) / 0.100 = 764.7 N/C, the direction is upward

g and the electric field in this region is constant and uniform.What are the magnitude and direction of the electric field?



hey , the answer is c

colorectal cancer may also develop from areas of abnormal cells in the lining of the colon or rectum. this area of abnormal cells is called dysplasia and is more commonly seen in people with certain inflammatory diseases of the bowel such as crohn's disease or ulcerative colitis.