The normal force equals the magnitude of the gravitational force as a roller coaster car crosses the top of a 40-m-diameter loop-the-loop. what is the car's speed at the top?

The car's speed at the top if the  normal force equals the magnitude of the gravitational force is 14m/s

According to the question, we are told that the normal force is equal to the magnitude of the gravitational force as a roller coaster.

N = G

The formula for calculating the normal force is expressed as:

N = mg

The formula for calculating the gravitational force is expressed as:

G =

If they are both equal, hence;

Given the following parameters

diamater = 40m

radius = 20m

acceleration due to gravity g = 9.8m/s^2

Substitute the given parameters into the formula to get the car's speed

Hence the car's speed at the top if the  normal force equals the magnitude of the gravitational force is 14m/s

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Explanation:

Given

Diameter

radius

From diagram, at top point

If Normal force is equal to Gravitational force

where N=normal reaction

m=mass of car

Normal reaction will provide centripetal force

thus

r = ρ x length / area  

ρ = r x area / length  

ρ is in ohm-meters  

in basic units, it is m³kg/s³a²  

i think this is it.