What is the horizontal acceleration of a ball that is launched horizontally with a velocity of 5.6 m/s?

Explanation:

When an object is launched under the action of gravity, the path followed by it is called projectile motion. The horizontal component of velocity is given by :

is the angle made with horizontal

In case of projectile motion, the velocity of projectile is constant in horizontal direction. As a result the rate of change of velocity will be equal to 0. So, the horizontal acceleration of a ball that is launched horizontally is 0. Hence, this is the required solution.

the order for strong to weak forces such as

strong nuclear force → electromegnetic force → weak nuclear force → gravitational force

the fundamental forces are those forces that act between to objects or element to make interactions. there are four types of fundamental forces such as strong and weak nuclear forces (due to protons and electrons), electromagnetic force (due to the motion of electrons) and gravitational force (due to orbital movement of the planet). if these forces are arranged on the basis of their maximum strength then the order is

strong nuclear force → electromegnetic force → weak nuclear force → gravitational force