A14000n car traveling at 25m/s rounds a curve of radius 200m. find the following: a. the centripetal acceleration of the car.

b. the force that maintains centripetal acceleration.

c. the minimum coefficient of static friction between the tires and road that will allow the car to round the curve safely.

a. The centripetal acceleration of the car is equal to 3.125

b. The force that maintains centripetal acceleration is equal to 1400 kilograms.

c. The minimum coefficient of static friction between the car tires and road is equal to 0.31.

Given the following data:

Scientific data:

a. To determine the centripetal acceleration of the car:

Mathematically, the centripetal acceleration of an object is given by the formula:

Where;

Substituting the given parameters into the formula, we have;

b. To determine the force that maintains centripetal acceleration:

First of all, we would find the mass of the car.

Mass = 1400 kilograms.

Note: The force that maintains centripetal acceleration is a centripetal force.

Mathematically, centripetal force is given by the formula:

c. To determine the minimum coefficient of static friction between the car tires and road:

Minimum coefficient of static friction = 0.31

Read more on centripetal acceleration here: link

Explanation:

Given

Weight of car

mass of car

velocity of car

radius

(a)Centripetal acceleration is given by

(b)Force that provide centripetal acceleration

(c)Friction force between car and tires is given by

where =coefficient of static friction

N=normal reaction

Centripetal force will balance the friction force

b

step-by-step explanation: a third of 24 is 8, 8 times 3 is 24 so 8 - 2 would be 6