A51.9 kg pole vaulter running at 10.2 m/s vaults over the bar. the acceleration of gravity is 9.81 m/s 2 . if the vaulter’s horizontal component of velocity over the bar is 1.1 m/s and air resistance is disregarded, how high is the jump? answer in units of m.

h =  5.25 m

Explanation:

given,

mass of the vaulter, m = 51.9 Kg

speed of the vaulter, v = 10.2 m/s

acceleration due to gravity, a =9.81 m/s²

Speed when he is in air = 1.1 m/s

height of the jump = ?

to solve this question we will use conservation of energy

initial potential energy is equal to zero

     h =  5.25 m

Vaulter jump to the height of 5.25 m.

this means that the temperature of both substances will be equal