The velocity of a ball in the horizontal direction is given as the following function: v(t) = 20 + 3t3,where t is in seconds and the velocity is in meters per second. part (a) find the change in the position, in meters, between t = 0 and t = 5.5 s. part (b) find the acceleration in the horizontal direction, in meters per square second, at t = 0.part (c) find the acceleration in the horizontal direction, in meters per square second, at t = 5.5 s.

(a) 796.29 m.

(b) 0.

(c) 272.25 m/s^2

Explanation:

The position and acceleration functions can be derived from the velocity function by taking the integral and derivative, respectively.

(a) at t = 0: x(0) = C.

at t = 5.5:

So, the change in the position between t = 0 and t = 5.5 is 796.29 m.

(b) at t = 0: a(0) = 0.

(c) at t = 5.5:

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