Determine the length of the tungsten filament in a 100 watt lightbulb given: (i) the resistivity of tungsten is 5.6 × 10−8 ω · m, (ii) the filament diameter is 0.0018 inches, and (iii) that the filament temperature is about 2550°c when it is "on". show your work. how is possible to use this length filament in the bulb? explain! hint: assume a ambient temperature of 25°c and an operating voltage of 120vrms (more on this and you will have to look up the temperature coefficient of tungsten to complete the calculations.

0.34148 m

Explanation:

= Resistivity of tungsten =

d = Diameter = 0.0018 inch

r = Radius =

= Temperature coefficient of tungsten =

Power is given by

We have the equation

Resistance is given by

The length of the filament is 0.34148 m

work: w = fd (given)

work done by chet   =50*1 = 50 j

work done by mika =40*2 = 80 j

work done by sara =30*1.5 = 45 j

work done by bill =60*0.5 = 30 j

students in order from the greatest amount of work done to the least is mika> chet> sara> bill

hence option (b) is correct.

are there options? cause you ain’t. real specific