An object releases from rest at a height of 0.5km .how long does it take to reach the ground

t = 10s

Explanation:

Assuming there's no air resistance,

Initial velocity (u) = 0 m/s

Acceleration by gravity (a) = 9.81 m/s^2

Displacement (s) = 500m

Time taken (t) = ?

Now,

Use formula,

s = u×t + (1/2)×a×t^2

s = 0×t + (1/2)×9.81×t^2

500 = 4.905×t^2

t = 10s

energy stored in the capacitor= 9.72 x 10⁻⁴ j

explanation:

the energy stored in the capacitor is given by

e= 1/2 c v²

e= energy stored

c= capacitance= 1.5 µc= 1.5 x 10⁻⁶f

v= potential difference=36 v

so energy stored= e= 1/2 (1.5 x 10⁻⁶) (36)²

energy stored= 9.72 x 10⁻⁴j