In 1990 walter arfeuille of belgium lifted a 281.5 kg object through a distance of 17.1 cm using only his teeth. a. how much work did arfeuille do on the object? b. what magnitude force did he exert on the object during the lift, assuming the force was constant?

(a) Work done is 471.74 J

(b) 2.758 kN

Solution:

As per the question:

Mass of the Walter Arfeuille, m = 281.5 kg

Distance, d = 17.1 cm = 0.171 m

Now,

(a) To calculate the work done:

Weight of Walter Afrueille, w = mg =

Work done is given by:

W = mgd = wd

(b) To calculate the magnitude of force exerted by Walter Arfeuille on the object is equal to the his weight:

F = w = mg =

F = 2.758 kN

we're given that v₀ = 0 and a = 5.4 m/s². therefore, since v = at + v₀ for constant acceleration the equation for velocity is

after 28s,

m/s

which i would round to 150 m/s as my final answer

can u provide the graph and if its not possible

then i can tell u the segment where the

average time interval starts degrading is the segment where the car is slowing down