A200 kg stationary cannon fires a 12 kg cannonball to the right at 300 m/s. explain. a) calculate the momentum of the cannon before the collision. b) calculate momentum of the cannonball before the collision. c) calculate the total kinetic energy before the collision. d) calculate the momentum of the cannon after the collision.

a) Since before collision the velocity of the cannon is zero and we know that momentum is the product of mass and velocity so its momentum is also zero.

b) Since before collision the velocity of the cannonball is zero and we know that momentum is the product of mass and velocity so its momentum is also zero.

c)

d)

Explanation:

Given:

mass of the cannon,

mass of cannonball fired,

velocity of cannonball,

a)

Momentum of the cannon before collision:

Since before collision the velocity of the cannon is zero and we know that momentum is the product of mass and velocity so its momentum is also zero.

b)

Since before collision the velocity of the cannonball is zero and we know that momentum is the product of mass and velocity so its momentum is also zero.

c)

The velocity before collision is zero.

kinetic energy is given as:

d)

Momentum of cannon after collision:

considering the collision to be elastic, its momentum will be equally opposite of the cannonball:

the electric field is a “force field” around a charged object that illustrates the direction the electric force would push an imaginary