Apitcher draws back his arm 0.5 m and then pitches a 0.5 kg baseball at 40 m/s, releasing the ball 1 m in front of his body. what is the average force being applied by the pitcher?

F = 266.67 N

Explanation:

given,

mass of the baseball = 0.5 Kg

speed of the baseball = 40 m/s

total displacement of the pitchers hand = 1 + 0.5 = 1.5 m

average force applied by the pitcher = ?

we know,

Work done is equal to change in kinetic energy, wheres as the initial velocity of the ball is zero.

W = KE

we know work done is equal to Force x displacement

    F x 1.5 = 400

    F = 266.67 N

the average force being applied by the pitcher is equal to F = 266.67 N

3.2x10^7

float.

archimedes' principle

denser than water sinks in water.

denser than mercury would sink in it