A7.00-kg bowling ball moves at 3.00 m/s. how fast must a 2.45-g ping-pong ball move so that the two balls have the same kinetic energy?

160.356ms^-1

Explanation:

kinetic energy in bowling ball is 1/2*m*v^2...

so,

0.5*7*3^2

0.5*7*9

31.5J

And if the ping pong ball has the same kinetic energy..

31.5J=0.5*0.00245*V^2

(mass of the ping pong ball is turned in to kg)

V^2 = 25 714.28...

therefore V = 160.356ms^-1

the force required to move the cart is divided by three or 33.33 n.

c

explanation: