Calculate the average value of an ac signal with a peak amplitude of 10v and a frequency of 10 khz.

V(average)=6.37 V

Explanation:

Given Data

Peak Voltage=10V

Frequency=10 kHZ

To Find

Average Voltage

Solution

For this first we need to find Voltage peak to peak

So

Voltage (peak to peak)= 2× voltage peak

Voltage (peak to peak)= 2×10

Voltage (peak to peak)= 20 V

Now from Voltage (peak to peak) formula we can find the Average Voltage

So

Voltage (peak to peak)=π×V(average)

V(average)=Voltage (peak to peak)/π

V(average)=20/3.14

V(average)=6.37 V

answer: 2×10^-2kg

explanation: density= mass per volume

vol=mass/density

converting to s.i units we have;

3÷1000kg = 0.003

1.5÷100m = 0.15

0.003/0.15 = 0.02kg