Arain cloud contains 5.32 × 107 kg of water vapor. the acceleration of gravity is 9.81 m/s 2 . how long would it take for a 2.07 kw pump to raise the same amount of water to the cloud’s altitude of 2.61 km? answer in units of s.

20.85 years

Explanation:

2.61 km = 2610 m

2.07 kW = 2070 W

First we need to calculate the potential energy required to take m = kg of rain cloud to an altitude of 2610 m is

With a P = 2070 W power pump, this can be done within a time frame of

or 658037739/(60*60) = 182788 hours or 182788 / 24 = 7616 days or 7616 / 365.25 = 20.85 years

acceleration = (change in speed) / (time for the change)

change in speed = (20-120)= -100 m/s.

1.5 min = 90 sec

acceleration = -100/90 = -1.11 m/s^2.

we don't care about the 150kg or the 2,500 meters. they don't make any difference.

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