Aspinning flywheel has rotational inertia i = 474.0 kg·m2. its angular velocity decreases from 26.2 rad/s to zero in 204.0 s due to friction. what is the frictional torque acting?

Explanation:

given,

rotational inertia, I = 474.0 kg·m²

decrease in angular velocity

ω₁ = 26.2 rad/s        ω₂ = 0 rad/s

time = 204 s

torque = ?

   α = 0.128 rad/s²

frictional torque acting by the flywheel is equal to 60.88 N.m

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