The work that must be done by an external agent to move a point charge of 2 mc from the origin
to a point 3 m away is 5 j. what is the potential difference between the two points?

(a) 4 × 10–4 v
(b) 10–2 v
(c) 2.5 × 103 v
(d) 2 × 106 v
(e) 6 × 106 v

(C) 2.5×10³ V

Explanation:

Potential difference: This can be defined as the work done in moving a unit charge from one point to another in an electric field. The unit of potential difference is Volt (V)

Mathematically, it is represented as shown below

V = W/Q Equation 1

Where V = potential difference, Q = charge, W = work done in moving the charge from one point to another in an electric field

given: Q = 2mC = 2×10⁻³ C, W = 5 J

Substituting these values into equation 1

V = 5/(2×10⁻³)

V = 2.5×10 V

Thus the potential difference between the two points = 2.5×10³ V

The right option is (C) 2.5×10³ V

can be answered using momentum.

momentum = p

p1= mass1 * velocity1

p1 = p2

therefore

p1 = 6kg * 4m/s

p1 = 24kgm/s

p2=m2 * v2

24 kgm/s = 7kg * v2

v2 = 24 kgm/s / 7kg

v2= 3.42 m/s

the temperature in kelvin of 2.0 dm3 of an ideal gas is doubled and its pressure is increased by a factor of four. what is the final volume of the gas