An object is dropped near the surface of a planet such that the gravitational field at the object’s location is 8 nkg. if the object is thrown upward at a speed of 20 ms, what is the position of the object in relation to the position in which the object was released and thrown upward after 3s ?
a- 96 m below the release position
b- 36 m below the release position
c-15 m above the release position
d- 24 m above the release position

D- 24 m above the release position

Explanation:

Given:

v₀ = 20 m/s

a = -8 m/s²

t = 3 s

Find: Δx

Δx = v₀ t + ½ at²

Δx = (20 m/s) (3 s) + ½ (-8 m/s²) (3 s)²

Δx = 24 m

answer: 802.3 kilo joules of energy represents 191.75 kilo calorie of energy.

explanation:

energy released during combustion of one mole methane = 802.3 kilo joules

if 1 kilo joule = 0.239006   kilo calorie

then ,802.3 kilo joule will be = 802.30.239006 kilo calorie

802.3 kilo joule = 191.75 kilo calorie

hence, the energy in kilo calorie is 191.75 kilo calorie.