In order to slide a heavy cabinet across the floor at constant speed, you exert a horizontal force of 600 n. is the force of friction between the cabinet and the floor greater than, less than, or equal to 600 n? explain your answer.

f=600 N

The frictional force will be equal to applied force in order to move cabinet at constant velocity.

Explanation:

According to Newton's Second Law of motion:

∑F=ma

where:

m is the mass

a is the acceleration

In our case Cabinet will move with constant velocity it means acceleration a=0

∑F=0

F-f=0

where:

F is the applied force

f is the frictional force in opposite direction of applied force (F).

600-f=0

f=600 N

The frictional force will be equal to applied force in order to move cabinet at constant velocity.

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