0.500 kg ball traveling at 1.00 m/s to the right hits a second ball of equal mass that is initially at rest. after the perfectly elastic collision, the second ball travels at 0.543 m/s at a 57.2o angle upward from the point of contact.
draw a before and after diagram of this collision.
write the momentum equations in both the x and y direction.
using the information from the previous problem, determine the speed and angle of the first ball.

electrical to thermal

yeet youwelcome broo

490 n

f=125n a=2.5m/s2

you'd use the equation that establishes a relationship between  energy  and  wavelength, which looks like this

e=h⋅cλ, where

λ  - the wavelength of the photon; c  - the speed of light, usually given as  3⋅108m/s; h  -  planck's constant, equal to  6.626⋅10−34j s

plug the value you were given for the energy of the photon in the above equation to get the wavelength

e=h⋅cλ⇒λ=h⋅ce

λ=6.626⋅10−34js⋅3⋅108ms−1.257⋅10−24j=1.581⋅10−1m