Asmall metal sphere weighs .28 n in air and has a volume of13
cm3. how much will its apparent weight be whencompletely
submerged in water?

To solve this problem we will start by considering how to calculate the apparent weight. On the sphere this will then be given that the real weight is the sum of the apparent weight and the Buoyant Force. Therefore we will have to

Here

= True Weight

= Apparent Weight

= Buoyant Force

If we seek to find the apparent weight we will have to,

Remember that

V = Volume (Volume Sphere)

= Density (At this case water density)

g = Gravitational acceleration

Therefore the apparent weight will be 0.1526N

choosing tennis and golf balls is your inde choice.

their mass and volume are dep

i just did an experiment like this in my science class. also the answer is yes, it will get separated because they are two opposites meaning if they are opposite they can not attract.

hope this .!