Ametal block of density 6000kg/m3 and mass 1.2kgis
suspended through a spring of spring constant 200n/m.
thespring-block system is dipped in water kept in a vessel. the
waterhas a mass of 260g and the block is at a height 40cm above
thebottom of the vessel. if the support to the spring is
broken, calculate the rise in the temperature of water.
specific heat capacity of the block is 250j/kg-k and that
ofwater is 4200j/kg-k. heat capacities of the vessel and spring
arenegligible.

The temperature rise of the water is 0.0034K. This is considering the fact that when string support gets broken, the block falls into the water agitating it. This causes a uniform rise in temperature which is common to the metal block and water. This accounts for the small value of the rise in temperature of the system.

Explanation:

The steps for the solution to this problem can be found below. The principle of conservation of energy has been applied in solving this problem (potential energy is converted to thermal or heat energy). Thank you.

falling water hydro = water .. spectcular places these plants are

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