How many
kilometers per liter will a car obtain if its engine is 25percent
efficient and it encounters and average force of 1000newtons?
assume the energy content of gasoline is 40,000,000 joulesper liter
(j/l).

10 km/L

Explanation:

Given the following from question:

Efficiency of car engine = 25% = 0.25

Average force = 1000 N

Gasoline energy content = 40,000,000 J/L

therefore:

Energy utilized effectively = Efficiency of car engine * Gasoline energy content

Energy utilized effectively = 0.25 * 40,000,000 = 10,000,000 J/L

Distance obtain by car in kilometer per meter =  Energy utilized effectively/Average force

Distance obtain by car in kilometer per meter = 10,000,000/1000 = 10,000 m/L = 10 km/L

10,000 meter per liter = 10 kilo meter per liter

i had this question and the answer was 3.15 miles.

martina travels from school to her mom's office. from there, she walks to school. after school, she walks to the library and then to a friends house before finally ending back at home. find martina's total distance traveled.

a) 0 miles  

b) 0.4 miles  

c) 1 mile  

d) 3.15 miles