A20 kg satellite has a circular orbit with a radius of
8.0*10^6 m and a period of 2.4 h around a planet of unknown mass.
ifthe magnitude of the gravitational acceleration on the surface
ofthe planet is 8.0m/s^2, what is the radius of the planet?

Radius of the planet,

Explanation:

It is given that,

Mass of the satellite, m = 20 kg

Radius of the circular orbit,

Time period of the motion of satellite,

The acceleration on the surface  of the planet is,

The relation between the time period of the satellite and its radius is given by third law of Kepler as :

M is the mass of planet

The acceleration on the surface of planet is given by :

So, the radius of the planet is . Hence, this is the required solution.

an energy transformation flow diagram is shown

where is it ?

the area between the graph and the t axis