Determine the amount of heat transfer required to convert 200
g(0.200kg) of ice to vapor if the initial temperature of the ice
is25 degrees c and the final temperature is 100 degrees c. note
thatthere is a 50 g (0.050kg) aluminum container holding the
initiallyfrozen water and that it is always in thermal equilbrium
withsample of water.

31.62 kJ

Explanation:

Step 1: identify the given parameters

mass of ice = 0.2 kg

Initial temperature of ice (T₁) = 25 ⁰C

Final temperature of ice (T₂) = 100 ⁰C

specific heat capacity of ice (Cp) = 2.108 kJ/kgK

Heat required to convert the ice (H) = ?

Step 2: calculate the amount of heat required to convert the ice

H = M*Cp*ΔT

H = 0.2*2.108*(100-25)

H = 31.62 kJ

Note: the aluminum container is in thermal equilibrium with the initial frozen water, hence they are at the same temperature. For this reason, the container will not affect the temperature of the frozen ice.

when the velocity of a mass on a spring is zero, the acceleration is at a maximum .

1 - wave length

2 - amplitude

3 - crest

4 - trough

explanation:

duh.