Apeg is located a distance h directly below the point of attachment of the cord. if h = 0.760 l, what will be the speed of the ball when it reaches the top of its circular path about the peg?

Explanation:

Given

Pivot is at h=0.76 L

Where L is the length of String

Conserving Energy at A and B

where u=velocity at bottom

After coming at bottom the ball completes the circle with radius r=L-0.76 L

Suppose v is the velocity at the top

Conserving Energy at B and C

Eliminating m

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measuring things 1 litre of water