Aparticle with a mass of 0.01 kg and a net charge of -0.05 c accelerates from rest through a uniform electric field. if the strength of the field is 2000 v/c, what is the speed of the particle after traveling for 0.5 m?

The speed of the particle after travelling for 0.5 m is 100 m/s.                            

Explanation:

It is given that,

Mass of the particle, m = 0.01 kg

Net charge on the particle, q = -0.05 C  

Electric field strength, E = 2000 V/C

Distance travelled by the particle, d = 0.5 m

The work done due to motion of the particle is balanced by the change in kinetic energy as :

v is the speed of the particle

F is the electric force

v = 100 m/s

So, the speed of the particle after travelling for 0.5 m is 100 m/s. Hence, this is the required solution.

c. newton's third law of motion

the answer is f1 and d2 because if you put equal force on those two points the beam would balance trust me on this