Alate traveler rushes to catch a plane, pulling a suitcase with a force-directed 30.0 degrees above the horizontal. if the horizontal component of the force on the suitcase is 60.6 n, what is the force exerted on the handle?

F=  69.97 N

Explanation:

Given that

θ = 30°

Horizontal component of the force (F) = 60.6 N

Lets take force exerted on the  suitcase= F

The horizontal component = F cosθ

Given that

F cosθ= 60.6 N

F cos 30°= 60.6 N

We know that cos 30° = 0.866

F x 0.866 = 60.6 N

F=  69.97 N

Therefore the force on the suitcase will be 69.97 N

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hope this : )

the working equation for the angular size is the product of the physical size and 360 degrees divided by the product of two pi and distance from earth. the minimum size would be 0.559 degrees while the maximum size would be 0.49 degrees.