Ahydraulic press has one piston of diameter 2.0 cm and the other piston of diameter 16.0 cm. what force must be applied to the smaller piston to obtain a force of 3200 n at the larger piston?

The force applied to the smaller piston = 2512 N

Explanation:

Hydraulic press:  A hydraulic press is a device used to produce a very large force. A hydraulic force operates based on pascal's principle.

F/f = A/a Equation 1

making f the subject of the equation above

f =(F×a)/A Equation 2

Where F = Force on the larger piston, f = force on the smaller piston, A = area of the larger piston, a = area of the smaller piston.

Given: F = 3200 N,  and

Area (A) = πD²/4 where D = 16.0 cm = 0.16 m

A = 3.143×(0.16)²/4 = 0.02 m²

Also

a = πd²/4 where d = 2 cm = 0.02 cm

a = 3.143×(0.02)²/4

a = 0.0157 m²

Substituting these values into equation 2

f = (3200×0.0157)/0.02

f = 2512 N

The force applied to the smaller piston = 2512 N

fgravity=10x10=100n case 1

fgravity=30x20=600n case 2

6 times more

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